find no. of terms 7,13,19...........205
Answers
Answered by
300
Hey there !!
A.P. 7 , 13 , 19 , ...... , 205
a = 7
d = 13 – 7 = 6
An = 205
As we know,
An = a + (n–1) d
205 = 7 + (n–1) 6
=> 205 – 7 = (n–1) 6
=> 198 = (n–1) 6
=> n–1 = 198 / 6
=> n–1 = 33
=> n = 33 + 1
=> n = 34
Thus, total no. of terms is 34.
A.P. 7 , 13 , 19 , ...... , 205
a = 7
d = 13 – 7 = 6
An = 205
As we know,
An = a + (n–1) d
205 = 7 + (n–1) 6
=> 205 – 7 = (n–1) 6
=> 198 = (n–1) 6
=> n–1 = 198 / 6
=> n–1 = 33
=> n = 33 + 1
=> n = 34
Thus, total no. of terms is 34.
Answered by
2
Answer:
We will get the number of terms in the given sequence to be 34.
Step-by-step explanation:
- As per the question we have to evaluate the given data.
Given data:- 7,13,19....205.
To find:- Find no. of terms 7,13,19...205.
Solution:-
For this A.P.
a=7
d=a2-a1=13-7=6
Let there are n term in this A.P.
last term is 205
We know that
205= a+(n-1)d
Therefore given series has 34 terms in it,
Similar questions