Question

A PENDULUM OSCILLATES 30 TIMES IN 3 SECONDS. FINDS ITS TIME PERIOD AND FREQUENCY.

Answer 1

Answer:

The pendulum oscillates 30 times in 3 secs.

so taken taken to oscillate once =3/30 secs =0.1 secs

so time period of the pendulum is 0.1 secs.

Frequency =1/time period=1/0.1 Hz =10 Hz

We get, 10 Hz.

Hope it helps have a sweet day..............

Answer 2

Given:

• Pendulum oscillates 30 times in 3 seconds.

To find:

• Time period
• Frequency

Calculation:

Time period is defined as the time taken by an oscillatory body to complete one full oscillation.

$time \: period = \dfrac{total \: time}{no. \: of \:oscillations }$

$\implies time \: period = \dfrac{3}{30}$

$\implies time \: period = 0.1 \: sec$

Now, frequency is defined as the total number of oscillations completed in one second. In other words, it is the reciprocal of time period.

$frequency = \dfrac{1}{time \: period}$

$\implies frequency = \dfrac{1}{0.1}$

$\implies frequency = 10 \: hz$

So, time period is 0.1 seconds and frequency is 10 Hz