Question

A pendulum oscillates 40 times in 4 seconds .find its time period and frequency​

Answer 1

Frequency=40vibration/4sec=10 hertz

Answer 2

$\huge{\bold{\underline{\underline{Solution:-}}}}$

$\large{\bold{\underline{To find }}}$

${ \nu \: (frequency)}$ = ?.

Time period(T) = ?.

$\large{\bold{\underline{\underline{Step - by - Step - Explanation}}}}$

Frequency:-

• Frequency is defined as the number of oscillations of a vibrating body per second.

So,

$\huge{\boxed{\boxed{ \nu = \frac{Number \: of \:oscillations}{Total \: time}}}}$

Substituting the values.

${ \nu = \frac{40}{4}}$

${ \nu = 10 \:Hz}$

$\huge{\boxed{\boxed{ \nu = 10 \:Hz}}}$

So,the frequency of pendulum is 10 Hertz.

Time period:-

•  It is given by the inverse of the frequency.

$\huge{\boxed{\boxed{ T = \frac{1}{ \nu}}}}$

Substituting the values.

${T = \frac{1}{10}}$

${T = 0.1 \: seconds}$

$\huge{\boxed{\boxed{T = 0.1 \:Seconds}}}$

So,the Time period of pendulum is 0.1 seconds.