Question

a pendulum oscillates 40 times in 4 seconds .find its time period and frequency?

Answer 1

first find the length by dividing 40 and 4 that is L=10m
then period of pendulum is calculated by T=2pi root(L/g)
then frequncy is reciprocal of time period that is 1/T
my calculated time period is 6.26sec and frequncy is 0,159hz
hope the answer is correct.

Answer 2

${ \huge\fbox \pink {A}\fbox \blue {n} \fbox\purple {s} \fbox \green{w} \fbox \red {e} \fbox \orange {r}}$

$\bold{Time\:period}$=$\large\bold{\frac{t}{Number\:of \: oscillations\:in\:time\:t}}$

=$\large\bold{\frac{4}{40}}$= $\bold{0.1\:s}$

$\bold{Frequency}$= $\large\bold{\frac{1}{Time\:period}}$= $\bold{10\:Hz}$