Fɪɴᴅ ᴛʜᴇ ᴘᴏɪɴᴛ ᴏɴ ᴛʜᴇ ᴀxɪs ᴡʜɪᴄʜ ɪs ᴇϙᴜɪᴅɪsᴛᴀɴᴛ ғʀᴏᴍ (2,-5) ᴀɴᴅ (-2,9)
plz no irrelevant answers I will report that answer..
Answers
Answered by
5
Answer:
(7/5, 2/5, -16/5)
Step-by-step explanation:
ratio = 2:3
points = ( m×1 +m× 2 /m+n, my1+my 2 / m + n, mz1+ mz2 / m+n)
= 2×2+3×1/5, 2×-5+3×4/5, 2×1+3×-6/5
(7/5, 2/5, -16/5)
Answered by
10
Answer:
Given points A(2,−5) and B(−2,9)
Let the points be P(x,0)
So, AP=PB and AP²=PB²
⇒(x-2)² + (0+5)² = (x+2)² + (0-9)²
⇒x² +4−4x+25= x² +4 +4x +81
⇒x² +29- 4x = x² +85+4x
⇒-4x−4x=85−29
⇒−8x=56
⇒x=−7
Hence point on the axis which is equidistant from (2,-5) and (2,-9) is (-7,0).
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