Math, asked by Anonymous, 8 months ago

Fɪɴᴅ ᴛʜᴇ ᴘᴏɪɴᴛ ᴏɴ ᴛʜᴇ ᴀxɪs ᴡʜɪᴄʜ ɪs ᴇϙᴜɪᴅɪsᴛᴀɴᴛ ғʀᴏᴍ (2,-5) ᴀɴᴅ (-2,9)




plz no irrelevant answers I will report that answer..​

Answers

Answered by sivasanjana
5

Answer:

(7/5, 2/5, -16/5)

Step-by-step explanation:

ratio = 2:3

points = ( m×1 +m× 2 /m+n, my1+my 2 / m + n, mz1+ mz2 / m+n)

= 2×2+3×1/5, 2×-5+3×4/5, 2×1+3×-6/5

(7/5, 2/5, -16/5)

Answered by Anonymous
10

Answer:

Given points A(2,−5) and B(−2,9)

Let the points be P(x,0)

So, AP=PB and AP²=PB²

⇒(x-2)² + (0+5)² = (x+2)² + (0-9)²

⇒x² +4−4x+25= x² +4 +4x +81

⇒x² +29- 4x = x² +85+4x

⇒-4x−4x=85−29

⇒−8x=56

⇒x=−7

Hence point on the axis which is equidistant from (2,-5) and (2,-9) is (-7,0).

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