Question

A pendulum strikes 5 times in 3 seconds and another pendulum strikes 7 times in 4 seconds . If both pendulum start striking at the same time , How many clear strikes can be listened in 1 minutes ?​

Answer 1

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A pendulum strikes 5 times in 3 seconds and another pendulum strikes 7 times in 4 seconds . If both pendulum start striking at the same time , How many clear strikes can be listened in 1 minutes ?

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Given:

First pendulum strikes once in 3/5 seconds

Second pendulum strikes onec in 4/7 seconds .

LCM. of 3/5 and 4/7 = LCM. of 3 and 4/HCF. of 5 and 7 = 12.

Step by step solution:

So, they strike together after every 12 seconds.

Thus, they strike ( 60/12 + 1 ) = 6 times in 1 minute

Total number of clear strike heard

= [ 60/(3/5) + 60/(4/7) ] - 6 = 60 * 5/3 + 60 * 7/4 ) - 6

= 100 + 105 - 6 = 199

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Hope my answer will be helpful for you thanks . . .

Answer 2

Answer:

First pendulum strikes once in 3/5 seconds

Second pendulum strikes onec in 4/7 seconds .

LCM. of 3/5 and 4/7= LCM of 3 and 4/HCF. of 5 and 12.

So, they strike together after every 12 seconds.

Thus, they strike ( 60/12 + 1 ) = 6 times in 1 minute

Total number of clear strike heard

= [ 60/(3/5) + 60/(4/7) ] - 6 = 60 * 5/3 + 60 * 7/4 ) - 6

= 100 + 105 - 6 = 199