Question

A penny is dropped from the top of the Empire State Building in New York City (h=381 m). Knowing that gravity accelerates the penny at a rate of –9.8 m/s 2 , with what velocity does the penny hit the ground? How long does it take to hit the ground?

Answer 1

Answer:

Given:

Height=381m

Acceleration due to gravity= -9.8 m/s^2

Explanation:

By v^2-u^2=2as

v=√(2as+u^2)

Since in free fall (ball is dropped the initial velocity is zero)so u=0

v=√(2as)

v=√{2(-9.8)(-381)}As the penny is falling from a height displacement should be taken as negative(-381)

v=86.4 m/s

t=(v-u)/a

t=86.4÷9.8

t=8.8 sec

Hope it helps

PLS MARK ME AS BRAINLIEST