Question

a pentagonal park.Neha and Nidhi divided it in two different ways to find its area.

Answer 1

Consider the given pentagonal park.

Let us find the area of the park which Neha divided.

Neha divided the pentagonal park into two trapezoids.

So, area of the park = $2 \times$ Area of trapezoid

= $2 \times \frac{(a+b) h}{2}$

where 'a' and 'b' are the lengths of the parallel sides of the trapezoid and 'h' is the height

= $2 \times \frac{(15+28) \times 6}{2}$

= 258 square meters.

Now, let us find the area of the park which Nidhi divided. Nidhi divided the park into one triangle and one rectangle.

So, area of the park = area of triangle + area of rectangle

= $\frac{1}{2} bh + lw$

where 'b' is base and 'h' is height of the triangle and 'l' is length and 'w' is width of the rectangle.

=$(\frac{1}{2} \times 12 \times 13) + (15 \times 12)$

= $78 + 180$

= 258 square meters.

So, the area of the given pentagonal park is 258 square meters,

Answer 2

Hope it may help you

Please mark me as brainlist