Question

A perfect gas at 27 degrees c is heated at constant pressure till its volume doubled final temperature is

Answer 1

. V1/V2=T1/T2. equation 1

V1 is the initial volume=V

V2 is the final volume= 2V

So , according to the equation

V/2V=(27+273)K/T2

1/2=300/T2

T2=600K...

So T2 i.e. final temperature is 600K or 327°C....

Hope this was helpful^_^

Happy learning

Answer 2

Concept Introduction:-

An object's temperature is a number representing its temperature.

Given Information:-

We have been given that A perfect gas at $27$ degrees c is heated at constant pressure.

To Find:-

We have to find that final temperature.

Solution:-

According to the problem

The equation is

$\frac{V_1}{V_2}=\frac{T_1}{T_2}$

$V_1$ is the initial volume$=V$

$V_2$ is the final volume$= 2V$

So, according to the equation

$\frac{V}{2V}=\frac{(27+273)K}{T_2}\\\frac{1}{2}=\frac{300}{T_2}\\T_2=600K$

So $T_2$ i.e. final temperature is $600$ K or $327$°C.

Final Answer:-

The final temperature is $600$ K or $327$°C.

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