Question

A perfectly cubical Gaussian surface has an electric dipole (two charges (±Q) of equal size put opposite signs separated by a distance l ) at its geometric center. The total Electric flux through all of the six faces of the cube is

Answer 1

Answer:

The net total electric flux will be zero.

Explanation:

According to Gauss Law, Electric flux, Φₑ through a gaussian surface is given by

Φₑ = Q/ε₀

where Q is the net electric charge enclosed. Since an electric dipole is placed inside the cube, net charge inside the cube is zero ie Q = 0. So

Φₑ = 0

Hence net electric flux through all surfaces of the cube is zero.