Question

write a program that print a shaped like diamond of numbers the program should accept a number and from user and display a diamond of dimension and then output should be (e.g. if N=4)
1
1 21
12321
1234321
12321
121
1
​

Answer 1

Answer:

# Python program to

# print Diamond shape

# Function to print

# Diamond shape

def Diamond(rows):

n = 0

for i in range(1, rows + 1):

# loop to print spaces

for j in range (1, (rows - i) + 1):

print(end = " ")

# loop to print star

while n != (2 * i - 1):

print("*", end = "")

n = n + 1

n = 0

# line break

print()

k = 1

n = 1

for i in range(1, rows):

# loop to print spaces

for j in range (1, k + 1):

print(end = " ")

k = k + 1

# loop to print star

while n <= (2 * (rows - i) - 1):

print("*", end = "")

n = n + 1

n = 1

print()

# Driver Code

# number of rows input

rows = 5

Diamond(rows)

Answer 2

Python program to solve Numerical Diamond problem.

Language used: Python 3.0

Program:

n=int(input())

sp=n-1

l=[]

for  i in range(1,n+1):

   jj=''

   kk=''

   spp= ' ' * sp

   print(spp,end='') #Starting spaces

   for j in range(1,i+1): #first half elements of each row string 1234

       print(j,end='')

       jj=jj+str(j)

   for k in range(1,i):  #second half of each row's string [321]

       print(k,end='')

       kk=kk+str(k)

   l.append(spp+jj+kk)       #appending the complete row

   #[spaces inc] to use them in printing next half of the diamond

  print(end='\n')

   sp=sp-1

#Printing the next half of the diamond  

#As we dont need the middle row to be repeated, take n-1 rows only.

#And as they need to be printed in reverse order, reverse the list

l=l[:-1][::-1]

for i in l:

   print(i)

Testcases:

Input1:

1

Output1:

1

Input2:

2

Output2:

1

121

1

Input3:

3

Output3:

 1

121

12321

121

 1

Input4:

4

Output4:

  1

 121

12321

1234321

12321

 121

  1

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