(a) perimeter (b) area (c) actual perimeter and the area if a = 4 cm, b= 2 cm and c=3 cm
One side of a square is (2a + 3b-C) cm. Find its
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7 is answer of one side of square
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side = 2a+3b-c
perimeter= 4(2a+3b-c)
putting the value of a, b, c
=4(2*4+3*2-3)
=4*11
=44
area= (2a+3b-c) (2a+3b-c)
=(2*4+3*2-3)(2*4+3*2-3)
=11*11
=121
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