A perimeter of an isosceles triangle is 32 cm and base is 12 cm one of its equal sides forms diagonal of parralogram find area of parallelogram.
Answers
Area of Parallelogram = 2 * 48 = 96 cm²
Step-by-step explanation:
A perimeter of an isosceles triangle is 32 cm and base is 12 cm
=> Other two sides are = (32 - 12)/2 = 10 cm
Diagonal of a parallelogram divides in two two Equal Areas
Hence area of parallelogram = 2 * area of Isosceles triangles
Side of isosceles triangle = 12 , 10 , 10 cm
s = (12 + 10 + 10)/2 = 16
Area of isosceles triangle = √16(16-12)(16-10)(16-10)
= √(16 * 4 * 6 * 6)
= 4 * 2 * 6
= 48
Area of Parallelogram = 2 * 48 = 96 cm²
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