Question

Obtain the sum of first 56 terms of an ap whose 19 term is 52 and 38 term is 148 respectively

Answer 1

Answer:

200

Step-by-step explanation:

T n=a+(n−1)d

Given,

T 38=a+37d=128...(1)

T 19 =a+18d=52...(2)

(1)-(2) gives,

d=4

From (2)

a=52−18(4)=−20

∴T 56​

=a+(56−1)d

=−20+55×4

=200

Answer 2

Thanks for this In 4732 aman