a person applies for two jobs A and b.the probability of his selection for job A and job B respectively 7/10 and 5/10.if probability of that at least one application is rejected 6/10. then find the probability of that he will be selected in one of two jobs
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Answer:
0.8
Step-by-step explanation:
Let A and B denote the events that the person is selected in firms X and Y respectively.
Then in the usual notations, we are given:
P(A)=0.7⇒P(
A
)=1−0.7=0.3
P(
B
)=0.5⇒P(B)=1−0.5=0.5
and P(
A
∪
B
)=0.6
The probability that the persons will be selected in one of the two firms X or Y is given by:
P(A∪B)=1−P(
A
∩
B
)=1−(P(
A
)+P(
B
)−P(
A
∪
B
))
=1−(0.3+0.5−0.6)=0.8
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