A person at 20 m distance can see a tree top aligned with the top of the pole(length2.5m) placed on ground 5m away from that person towards the tree. The eye-level of the person is 2m from the ground . Determine the tree height.
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Answer:
Step-by-step explanation:
Let BC be the width of river. And ∡ of depression on either side of the river are 30
0
and 60
0
rube. It is given that
AC=20 m
Let BC=x CD=y ∠ABC=30
0
, ∠ABC=30
0
, ∠ADC=60
0
In △ABC,tanB=
BC
AC
=
x
20
=
3
1
⇒x=20
3
In △ADC,tan60
0
=
y
20
=y=
3
20
3
x+y=
3
80
m= width of river
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