a person boarded a train on 02.01.2015 at madgaon for nagercoil. the train departed from madgaon at 07:45 hours and reached nagercoil at 04:45 hours on the next fay, i. e. 03.01.2015. if the distance between these two syations is 1140 km the average speed of the train was approximately
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Answered by
7
Answer:
total distance = 1140 km
total time taken= 21 hours
average speed = distance/time
=1140/21
=58.28 km/hour
Answered by
5
The speed of the train is 54.28 km/hr
1) The speed of the train can be calculated by dividing the total distance covered by the total time taken by train.
2) The total Distance between the two stations is given as 1140 km
3) The total time taken by train would be 4:45-7:45 = 21 hours
4) Hence the speed of train is 1140/21 or 54.28 km/hr.
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