A person, borrows Rs 15,000 paitly. at 10 fo and remaining at 12 of. If at the end of 2 years 6 months, he pays simple of R8 4050 horrow total how much did he interest at each rate ?
Answers
Explanation:
Let's denote the current age of Mohan as M and the current age of his son as S.
From the given information, we can write two equations:
After 5 years, the age of Mohan will be three times that of his son:
M + 5 = 3(S + 5)
5 years ago, Mohan's age was 7 times that of his son:
M - 5 = 7(S - 5)
We can simplify these equations as follows:
M + 5 = 3S + 15
M = 3S + 10
M - 5 = 7S - 35
M = 7S - 30
We can equate these two expressions for M to get:
3S + 10 = 7S - 30
Subtracting 3S from both sides, we get:
4S + 10 = -30
Subtracting 10 from both sides, we get:
4S = -40
Dividing both sides by 4, we get:
S = -10
This is not a valid solution, as the age of a person cannot be negative.
Therefore, there is no solution that satisfies the given conditions. It is likely that there is an error in the given information or some additional information is needed to solve the problem.
Patel Jivan
person, borrows Rs 15,000 paitly. at 10 fo and remaining at 12 of. If at the end of 2 years 6 months, he pays simple of R8 4050 horrow total how much did he interest at each rate ?
Let's denote the amount borrowed at 10% as x, and the amount borrowed at 12% as y.
We know that the total amount borrowed is Rs 15,000. Therefore, we can write:
x + y = 15,000 ...(1)
We also know that the interest on x for 2 years 6 months at 10% is given by:
Interest on x = (x * 10% * 2.5) = 0.25x
Similarly, the interest on y for 2 years 6 months at 12% is given by:
Interest on y = (y * 12% * 2.5) = 0.3y
We know that the total interest paid is Rs 8,405. Therefore, we can write:
0.25x + 0.3y = 8,405 ...(2)
We can solve these two equations to find the values of x and y.
Multiplying equation (1) by 0.3 and subtracting it from equation (2) multiplied by 10, we get:
10(0.25x + 0.3y) - 0.3x - 0.3y = 10(8,405) - 0.3(15,000)
Simplifying, we get:
2.5x = 2,855
Dividing both sides by 2.5, we get:
x = 1,142
Substituting this value of x in equation (1), we get:
y = 15,000 - x = 15,000 - 1,142 = 13,858
Therefore, the amount borrowed at 10% is Rs 1,142 and the amount borrowed at 12% is Rs 13,858.
To find the interest paid at each rate, we can substitute the values of x and y in the respective interest formulas:
Interest on x = 0.25x = 0.25 * 1,142 = Rs 285.50
Interest on y = 0.3y = 0.3 * 13,858 = Rs 4,157.40
Therefore, the person paid Rs 285.50 in interest on the amount borrowed at 10%, and Rs 4,157.40 in interest on the amount borrowed at 12%.Let's denote the current age of Mohan as M and the current age of his son as S.
From the given information, we can write two equations:
After 5 years, the age of Mohan will be three times that of his son:
M + 5 = 3(S + 5)
5 years ago, Mohan's age was 7 times that of his son:
M - 5 = 7(S - 5)
We can simplify these equations as follows:
M + 5 = 3S + 15
M = 3S + 10
M - 5 = 7S - 35
M = 7S - 30
We can equate these two expressions for M to get:
3S + 10 = 7S - 30
Subtracting 3S from both sides, we get:
4S + 10 = -30
Subtracting 10 from both sides, we get:
4S = -40
Dividing both sides by 4, we get:
S = -10
This is not a valid solution, as the age of a person cannot be negative.
Therefore, there is no solution that satisfies the given conditions. It is likely that there is an error in the given information or some additional information is needed to solve the problem.
Patel Jivan
person, borrows Rs 15,000 paitly. at 10 fo and remaining at 12 of. If at the end of 2 years 6 months, he pays simple of R8 4050 horrow total how much did he interest at each rate ?
Let's denote the amount borrowed at 10% as x, and the amount borrowed at 12% as y.
We know that the total amount borrowed is Rs 15,000. Therefore, we can write:
x + y = 15,000 ...(1)
We also know that the interest on x for 2 years 6 months at 10% is given by:
Interest on x = (x * 10% * 2.5) = 0.25x
Similarly, the interest on y for 2 years 6 months at 12% is given by:
Interest on y = (y * 12% * 2.5) = 0.3y
We know that the total interest paid is Rs 8,405. Therefore, we can write:
0.25x + 0.3y = 8,405 ...(2)
We can solve these two equations to find the values of x and y.
Multiplying equation (1) by 0.3 and subtracting it from equation (2) multiplied by 10, we get:
10(0.25x + 0.3y) - 0.3x - 0.3y = 10(8,405) - 0.3(15,000)
Simplifying, we get:
2.5x = 2,855
Dividing both sides by 2.5, we get:
x = 1,142
Substituting this value of x in equation (1), we get:
y = 15,000 - x = 15,000 - 1,142 = 13,858
Therefore, the amount borrowed at 10% is Rs 1,142 and the amount borrowed at 12% is Rs 13,858.
To find the interest paid at each rate, we can substitute the values of x and y in the respective interest formulas:
Interest on x = 0.25x = 0.25 * 1,142 = Rs 285.50
Interest on y = 0.3y = 0.3 * 13,858 = Rs 4,157.40
Therefore, the person paid Rs 285.50 in interest on the amount borrowed at 10%, and Rs 4,157.40 in interest on the amount borrowed at 12%.