Question

THE PRESENT AGES OF A AND B IN THE RATIO 7:5 TEN YEARS LATER THEIR AGES WILL BE IN THE RATIO 9:7 . FIND THEIR PRESENT AGES​

Answer 1

Answer:

LET A=SONU

B=MONU

Ratio in the present ages of Sonu and Monu = 7 : 5

Let age of Sonu = 7x years

and age of Monu = 5x years

10 years hence,

the age of Sonu = 7x + 10 years

and age of Monu = 5x + 10 years

According to the condition :

7x+105x+10=97

By cross multiplication,

7(7x+10)=9(5x+10)

⇒49x+70=45x+90

⇒49x−45x=90−70⇒4x=20

⇒x=204=5

∴ Sonu's present age =7x=7×5=35 years and Monu's present age =5x=5×5=25 years

Check : 10 years hence, their ages will be

Sonu's = 35 + 10 = 45 years

Monu's = 25 + 10 = 35 years

∴ Ratio 45 : 35 = 9 : 7          (Dividing by 5)

Step-by-step explanation:

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Answer 2

Answer:

A's age = 35

B's age = 25

Step-by-step explanation:

Given the present ages of 'a' & 'b' are in the ratio 7 : 5

Let the age be 7x : 5x

Ten years later their ages are in the ratio 9 : 7

⇒ 7x + 10 : 5x + 10 = 9 : 7

⇒ 7(7x + 10) = 9(5x + 10)

⇒ 49x + 70 = 45x + 90

⇒ 49x  45x = 90 - 70

⇒ 4x = 20

⇒ x = 5

So their ages are

7 × 5 = 35

5 × 5 = 25