A person buys a horse and a cart for rupees 1200 . he sells the horse at 12%profit and cart at 6% loss if he makes a6%on the whole find the cost of horse
Answers
Given :-
- Total CP = Rs.1200
- Sold Horse at = 12% Profit.
- Sold Cart at = 6% Loss .
- Whole Profit = 6% .
Solution :-
Let us Assume That, Cost Price of Horse was Rs.x .
→ Than, cost Price of Cart = Rs.(1200 - x)
Now, He Sold Horse at a Profit of 12%.
So,
→ SP = CP* (100+ Profit % ) /100
→ SP = x * (112)/100 --------------- Equation (1).
Now, He Sold Cart At a loss of 6% .
So,
→ SP = CP* (100 - Loss % ) /100
→ SP = (1200-x) * (94)/100 --------------- Equation (2).
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Now, Given That, Overall Profit was 6%.
So,
→ CP* (100+ Profit % ) /100
→ SP = 1200 * (106)/100 --------------- Equation (3)
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Adding Equation (1) & (2) now, And Putting Equal to Equation (3) , we get,
→ (112x)/100 + [1200-x)94]/100 = (1200*106)/100
→ 112x - 94x + 1200*94 = 1200 * 106
→ 18x = 1200 * 106 - 1200*94
→ 18x = 1200(106-94)
→ 18x = 1200 * 12
→ x = (1200*12)/18
→ x = Rs.800
Hence, CP of Horse was Rs.800.
Answer:
Step-by-step explanation:
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