A person cannot see objects clearly which are placed before 40 cm from him, the power of the lens to correct the vision is
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Answer:
A lens which can bring an object at infinity to 40 cm is required here.
So u=∞ and v=−40cm
we know
f
1
=
v
1
−
u
1
f
1
=
−40
1
−
∞
1
So f=−40cm=−0.4m
Power of lens P=
f
1
=1/−0.4=−2.5D
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