A person covers a certain distance at a certain speed. If he increases his speed by 25%, then he
takes 12 min less to cover the same distance. Find the time taken by him initially to cover the
distance travelling at the original speed.
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Step-by-step explanation:
ANSWER
Let n ve the event speed
Let T ve the time taken as speed
Let D ve the distance covered in T & x
Given
20minutes=
3
1
hourD=xT
(x+3)
D
=T−
3
1
x−2
D
=T+1/3
Adding the two equations we get
(x+3)(x−2)
D(2x+1)
=2T
(x+3)(x−2)
x(2x+1)
=2
2x
2
+x=2x
2
+2x−12
12=x
∴ Speed 12 km/hr
∴15T=D
18(T−1/3)=D
18T−6=D
3T−6=0
T=2hours
∴ Distance =24cm
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