Question

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A person divides 5 dozen apple
between his two sons A and B
in the ratio of their ages.
if the age of A is 18 years
and the age of B is 10
years find the number of apples
bought by A and B.​

Answer 1

5 dozens apples is 60 apples

sum of their ages 18+10=28

apples........

A=18/28÷60

i am sorry i cannot complete answer due to some emergency

Answer 2

Answer:

A's age = 18 years

B's age = 10 years

Ratio of their ages is 18 : 10 = 9 : 5

Total number of apples = 5 x 12 (as 1 dozen equals 12 objects ) = 60

From the above ratio, let A has 9x apples and B has 5x apples

9x + 5x = 60

14x = 60

x = 60/14 = 30/7

So, A has 9 x 30/7  = 38.6 = 39 ( approx.   as this type of answers are always in whole and not in fraction or decimal )

     B has 5 x 30/7 = 21.4 = 21 (  approx.   as this type of answers are always in whole and not in fraction or decimal )

To check whether the answer is correct or not, we will add up the two values = 39 + 21 = 60 ( Hence the answer is correct ) even 38.6 and 21.4 also equals to 60.

This is the correct answer.