Question

A person facing north walks 3km turn left and walk 4km again walks 3km after turning right then turns right and 12km what is the displacement from the starting point and which direction he is facing
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Answer 1

Answer:

please tell me the right answer

Answer 2

Given :

The person facing north walks 3km turn left and walk 4km again walks 3km after turning right then turns right and 12km

To find :

the displacement from the starting point and the direction he is facing

Solution :

The man starts from point A as shown in the picture and ends his journey at point E.

Therefore, the direction which he is facing at the end of his journey is towards the East as shown in the diagram.

We know , Displacement = The shortest distance of a body between the inital position and the final position.

The displacement of the body is AE.

Here AE is the hypotenuse of triangle AEF

The value of AE is :-

also according to Pythagoras theorem :

hypotenuse ^2 = height ^2 + base ^2

AE^2 = (12-4)^2 + (6+6)^2

AE^2 = 8^2 + 12 ^2

AE ^2 = 64 + 144

Therefore AE =

$: \sqrt{(64 + 144)} = \sqrt{208}$

=14.42 km approx

Therefore the displacement of the person is 14.42km approx

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