Question

A person gave 1/5 part of his money to 1st boy, 1/3 part to 2nd boy and 3/8 part to 3rd boy. rest 1200rs to his wife. how much money he had all?​

Answer 1

Answer:

Let the total is be y

Money given to 1st boy = 1/5 of y = y/5

Money given to 2nd boy = 1/3 of y = y/3

Money given to 3rd boy = 3/8 of y = 3y/8

Money given to wife = Rs. 1200

ATQ

y/5 + y/3 + 3y/8 + 1200 = y

25y+40y+45y/120 +1200 = y

110y/120 + 1200 = y

110y/120 - y = -1200

110y-120y/120 = -1200

-10y/120 = -1200

10y/120 = 1200

10y = 1200 x 120

y = 1200 x 120/10

y = Rs. 14400

Therefore, total money = y = Rs. 14400

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