Question

When photons of energy 4.25 ev strike the surface of a metal a?

Answer 1

Answer:

When photons of energy 4.25 eV strike the surface of a metal A. The ejected photoelectrons have

maximum kinetic energy (T(A) (expressed in eV) and de-Broglie wavelength (DA). The max kinetic

energy of photoelectrons liberated from another Metal B by photons of enegy 4.2 eV is Tg. Where

TB= (TA-1.5). If De-Broglie wave length of these photoelectrons ng Que =2).A), then which of the

following is not correct

(A) The work function of A is 2.25 eV. (B) The work function of B is 3.7 eV

(C) TA = 2.0 eV,

(D) TB =0.75 eV

14. material Ais 2 eV & Wo for another photoele

Explanation: