A ball of mass 200g is moving with a velocity of 10m/s is brought to rest in .04s.Calculate the impulse and average force exerted by the player/s
Answers
Answered by
1
Dear Student,
m=200 g=0.2 kgvi=10 m/svf=0△t=0.05 sImpulse, I=F.△t=m(vi−vf)I=0.2(10−0)=2 kg−m/sAverage force, F=Impulse△tF=20.05=40 N
m=200 g=0.2 kgvi=10 m/svf=0△t=0.05 sImpulse, I=F.△t=m(vi−vf)I=0.2(10−0)=2 kg−m/sAverage force, F=Impulse△tF=20.05=40 N
Similar questions