A and b can compete a piece of work in 12 and 18 days respectively. A begain to do the work and they work alternately one at a time for one day each. The whole work will be complete in
Answers
Answered by
0
A and B do same work
Work =LCM (12,18)=36
Per day work of A=36/12=3
Per day work of B=36/18=2
A begin to do work and they alternatively work on each day
Work in 2 days =5
Work in 2×7=14 days=5×7=35
Work left is 1
Now its A's turn to do work
A does 3 work per day
Therefore 1 work is done by 1/3 day
Therefore total days required=14+1/3
Answer is 14 1/3 days
Work =LCM (12,18)=36
Per day work of A=36/12=3
Per day work of B=36/18=2
A begin to do work and they alternatively work on each day
Work in 2 days =5
Work in 2×7=14 days=5×7=35
Work left is 1
Now its A's turn to do work
A does 3 work per day
Therefore 1 work is done by 1/3 day
Therefore total days required=14+1/3
Answer is 14 1/3 days
Similar questions