Question

A person gave 2/5 of his property to his elder son and 30% of his property to his younger son. He shared rest of the property among his three daughters in the ratio 3:5:2. If o one of his sons got 20,000 more than the other, the the largest share among the shares of the daughters is

Answer 1

Answer:

Step-by-step explanation:

Elder son got 40%

Younger son got 30%

Difference in share =10%=20000

So total was 20000*100/10=200000

Of which 70% was given to sons

Of the rest 30% daughter with highest share had 5/10th

So daughter with highest share had=(30/100)*(200000)*(5/10)=30000

Answer 2

The largest share among the shares of the daughters is Rs. 30000

Step-by-step explanation:

Let the total property be Rs. x

• The property that was given to the elder son $= \frac{2}{5}$

In terms of percentage, it would be $= \frac{2}{5} \times 100 = 40\%x$

• The property that was given to the younger son = 30% of x
• The property that was given to the daughters

= Total - the sons' share

$= 100 -(40+30) = 100-70 = 30\% x$

• The difference between the share of sons $= (40 - 30)\% = 10\%x = 20000$

Thus

$10\%x = 20000$

$\frac{10}{100}\times x = 20000$

$x = 200000$

So the total property was Rs 200000.

• Out of the daughters who received a 30% share, the daughter with the highest share received = $\frac{5}{10}$ the 30% of x

$= \frac{5}{10}\times \frac{30}{100} \times x$

$= \frac{5}{10}\times \frac{30}{100} \times 200000$

$= 30000$

• Thus, the largest share among the shares of the daughters is Rs. 30000.