Question

A person goes around the perimeter of a square park in exactly 1 minute. Each side of the park

measures 15 m. What will be the average velocity of the person after three and a half minutes?​

Answer 1

Refer to the attachment ⬆️

Answer 2

Given:

A person goes around the perimeter of a square park in exactly 1 minute. Each side of the park

measures 15 m.

To find:

Average velocity of the person after 3 and ½ minutes.

Calculation:

First , let's calculate the displacement after the given time.

Since the person completes one revolution in 1 minute , the same person will complete 3 revolution in 3 minutes.

Upto this, the displacement will be zero because the starting and the stopping point are same.

In the next half minutes , he will be on the opposite vertex of the square.

$\boxed{d = \sqrt{{15}^{2} + {15}^{2} } = 15 \sqrt{2} \: m}$

So, average Velocity

$avg. \: v = \dfrac{total \: displacement}{time}$

$= > avg. \: v = \dfrac{15 \sqrt{2} }{3 \frac{1}{2} \times 60 }$

$= > avg. \: v = \dfrac{15 \sqrt{2} }{210 }$

$= > avg. \: v = 0.101 \: m {s}^{ - 1}$

So, final answer is:

$\boxed{avg. \: v = 0.101 \: m {s}^{ - 1} }$