Question

a person goes from the house to the marks at a speed of 60 ms -1 and immediately return to the 40 ms -1 after the market is closed ​

Answer 1

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$\huge\color{cyan}\boxed{\colorbox{black}{♡Answer :-♡}}$

Average Speed =( V1 + V2 )/2

$v1 = 60 \: and \: \: v2 = 40 \\ \\ \frac{v1 + v2}{2} = \frac{60 + 40}{2} \\ \\ = \frac{100}{2} \\ \\ = 50 \: {msec}^{ - 1}$

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