Question

Find the number of tiles required to cover
a square floor of side 9 cm, if the dimension
of the tile are 15cm x 3cm. If each tile
costs ₹ 7 12.50, what is the total cost
incurred ?​

Answer 1

Step-by-step explanation:

area of square tile = 9 × 9

$= 81 \: {m}^{2}$

$= 81 \times 100 \times 100 \: {cm}^{2}$

$810000 \: {cm}^{2}$

area of tile = 15 × 3

$45 \: {cm}^{2}$

no.of tiles required

$= \frac{810000}{45}$

= 18000

cost of tiles

= 18000 × 712.50

= Rs. 12825000

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