Math, asked by nishajoshi1298, 1 year ago

A person has 15 acquaintances of whom 10 are relatives.in how many ways may be invite 9 guests so that 7 of them would be relatives? Chp - combination.plz answer


Anonymous: it's combination
Anonymous: isn't it
nishajoshi1298: Yes it is combination chp plz answer
Anonymous: i have answered

Answers

Answered by windyyork
22

There are 1200 ways to do so.

Step-by-step explanation:

Since we have given that

Number  of acquaintances = 15

Number of relatives in it = 10

Number of non relatives in it = 15-10 =5

Number of guests to be invited = 9

Number of relatives to be invited = 7

So, Number of ways would be

^{10}C_7\times ^5C_2\\\\=120\times 10\\\\=1200

Hence, there are 1200 ways to do so.

# learn more:

Mrs.william invited 120 guests who were either her relatives or her colleagues or both.if 60% of the guests were her colleagues and 20% of her relatives were her colleagues too,how many guests were her relatives?

https://brainly.in/question/6484241

Answered by sahiduzzamansaied
10

Step-by-step explanation:

This is your answer..Plz Mark as Brainleist thanks

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