Math, asked by bhb, 1 year ago

pls answerrrrrrrrrr this one plsssssssss fasttttttttttt​

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Answered by mysticd
0

Answer:

x²+1/x² = 6

Explanation:

i )x = √3+2√2

=> x = √2+1+2√2×1

=> x = √(√2)²+1²+2(√2)×1

=> x = √(√2+1)²

=> x = √2 + 1-----(1)

ii) 1/x = 1/(√2 + 1 )

= (√2-1)/[(√2+1)(√2-1)]

= (√2-1)/[(√2)²-1²]

= (√2 - 1 )/(2-1)

= (√2 - 1) ----(2)

iii )x + 1/x = √2 + 1 + √2 - 1

= 2√2 ----(3)

Now ,

x² + 1/x² = (x+1/x)² - 2

= (2√2)² - 2

= 8 - 2

= 6

Therefore,

x²+1/x² = 6

••••


bhb: why you subtracted it from two
bhb: and not added
mysticd: x² + 1/x² = (x²+1/x² + 2*x*1/x ) -2*x*1/x = (x+1/x)² - 2
mysticd: is it clear
bhb: yess
mysticd: :)
Answered by nalinsingh
0

Hey !

Refer the below attachment !

Thanks !

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