A person has 35000 that he has divided into three investment.part of the money is invested in a saving account with an annual rate of internet of 6% , part in 7% annual yield bonds, and the remainder in a business. In 2006 , when he lost 6% of the money that he invested in that business,his net income from all three investment was 660 . If he invested 3000 more in the business than in the savings account, how much was invested in each?
Answers
Given : A person has rupees 35000 that he has divided into three invests, part of the money is invested in a saving account with annual rate of interest of 6% , 7% annual yield Bond , lost 6% of the money that he invested in that business
To find : how much was invested in each
Solution:
Let say Amount invested are
1000x , 1000y & 1000z at 6 % , 7 % & - 6 %
1000x + 1000y + 1000z = 35000
=> x + y + z = 35
1000x *6/100 + 1000y*7/100 + 1000z(-6/100) = 660
=> 6x + 7y - 6z = 66
=> 6(x - z) + 7y = 66
1000z = 1000x + 3000
=> z = x + 3
=> x - z = - 3
6(x - z) + 7y = 66
=> 6(-3) + 7y = 66
=> 7y = 84
=> y = 12
x + y + z = 35 => x + y + x + 3 = 35 => 2x + y = 32
2x + 12 = 32
=> 2x = 20
=> x = 10
z = 13
10000 , 12000 , 13000
Rs 10000 invested in Saving account
Rs 12000 invested in Bond
Rs 13000 invested in Business
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