Question

a person has (7 a b + 5 BC + AC) rupees out of it he spend (a b + BC), (half AC - half BC), (a b + 2 B C - 3 AC) and (3 a b - half BC + 2 AC) rupees on different things how many Rupees he has now

Answer 1

He has now $2AB+3BC+\frac{3}{2}AC$ rupees

Step-by-step explanation:

Given,

Total money = (7 AB + 5 BC + AC) rupees.

Amounts( in rupees ) spent are,

(AB + BC), ($\frac{1}{2}$AC -

So, the total spending = (AB+ BC)+($\frac{1}{2}$AC -

$=5AB+(3BC-\frac{2}{2}BC)-\frac{1}{2}AC$

$=5AB+(3BC-BC)-\frac{1}{2}AC$

$=5AB+2BC-\frac{1}{2}AC$

So, the remaining amount = total amount - spending

$=7 AB + 5 BC + AC-5AB-2BC+\frac{1}{2}AC$

$=2AB+3BC+\frac{2+1}{2}AC$

$=2AB+3BC+\frac{3}{2}AC$

#Learn more:

Algebraic expressions subtraction :

https://brainly.in/question/12017719