Question

A person has some amount in his debit card. Before going for shopping, he
participated in a survey conducted by the mall with a condition that he should spend
at least x rupees. He could win some points so that his balance is doubled. As
per
che
deal he spends the money. He repeated the same with five different malls. Finally, he is
left with no money. What is the amount he had in his card and how much did he
spend at each mall. Remember that he spends the same amount at every mall.
O 30,31
O 16,30
O 31,16
O 31, 32
A copy of your responses will be emailed to the address that you provided.​

Answer 1

Answer:

1630 rs can be the answer but we will more confirm about it if tell us what is after per che

Answer 2

Answer: $\frac{x}{y} =\frac{31}{16}$

Step-by-step explanation:

As let, he has initially x rupees.

Let him spend y rupees at each mass.

As to the question,

At the first mall, he spends y, so he has now x-y rupees.

As it gets doubled ∴ he has 2(x-y)

At the second mall, he spent y

now he has 2(x-y)-y

it gets doubled, so he has 2(2(x-y)

At the third mall, he spends y

now he has 2(2(x-y)-y)-y

So it gets doubled, so he has =2(2(2(x-y)-y)-y).

So now at the fourth mall, he spent y,

now he has 2(2(2(x-y)-y)-y)-y)

As if it gets doubled, so he has 2(2(2(2(x-y)-y)-y)-y)

At the fifth mall, he spends y

now he has 2(2(2(2(x-y)-y)-y)-y)-y)

but now he has no money,

∴ 2(2(2(2(x-y)-y)-y)-y)-y=0

  2(2(2(2x-3y)-y)-y)-y)=0

  2(2(4x-7y)-y)-y=0

  2(8x+15y)-y=0

  16x-31y==n

   $\frac{x}{y} =\frac{31}{16}$

As the ratio of money he had had, the money he spent at each mass.

So he may have 3100  rupees and beginning and may spend 31, 16.      

  #SPJ3