Math, asked by ranjana28, 1 year ago

a person has some currency notes of domination rupees 500 rupees 100
and rupees 50 respectively the notes the ratio of the number of these notes is 3:4:5 if the total money is rupees 86000 find the numbers of the of nodes of each nomination​

Answers

Answered by Anonymous
3

Answer:

Step-by-step explanation:

Let the no of 500rs note = 2x So no of notes of 100rs= 3x And no of notes of 50 rs will be 5x Now,500×2x + 100×3x + 50×5x = 31000 So, 1550x =31000 X = 20 So no of Rs 500 note = 40 100 rs note = 60 50rs note= 100

Answered by dikshalipatel
5

Step-by-step explanation:

let the number of notes be x

.•. Number rupees 500 notes be 3x

number of rupees 100 notes be 4x

number of rupees 50 notes be 5x

.•. 500 × 3x + 100 × 4x + 50 × 5x = 86000

.•. 1500x + 400x + 250x = 86000

.•. 2150x = 86000

.•. x = 86000/2150

.•. x = 40

.•. Number rupees 500 notes = 3x = 3(40) = 120

number of rupees 100 notes = 4x = 4(40) = 160

number of rupees 50 notes = 5x = 5(40) = 200

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