Question

A person has three children with at least one boy find the probability of having at least two boys among the children

Answer 1

1 person = 3 children
1 of them is boy
probability of Haveing two boys
Formula = no. of event/ total no. of event
= 2/3
= 2:3

ans. 2:3

Answer 2

Answer:

Probability of having at least two boys among three children is 0.66

Step-by-step explanation:

Given, the person has 3 children and one among them is a boy

Hence, the possible outcomes are BBB, BBG, BGG. there are 3 outcomes

and the favorable outcomes are  BBB, BBG  

Also, number of favorable outcomes = 2

$p[E] = \frac{number \ of \ possible \ outcomes}{total \ number \ of \ outcomes}$

P[at least two boys among 3 children] = $\frac{2}{3}$

P[at least two boys among 3 children] = 0.66

Therefore, probability of having at least two boys among the children is 0.66