Question

a person has to go 50m due south,40m due west and 20m due north to reach his destinations.the displacement of person is

Answer 1

Refers to the attachment for the Answer.

From the attachment, Initial position of the Person is A and the Final Position is D.

We know that the Displacement is the shortest Distance between the Initial and the Final Position. 
∴ Displacement will be AD, since it is the Shortest distance between the Initial and the Final Positions. 

From the Figure,
AB = 50 m
AE = AB - BE
 = 50 - 20
 = 30 m

DE = CB = 40 m

In Δ ADE,
Applying Pythagoras theorem,
∴ AD² = AE² + DE²
⇒ AD² = (30)² + (40)²
∴ AD² = 900 + 1600
∴AD² = 2500
⇒ AD = 50

Hence, the displacement will be 50 m.


Hope it helps.

Answer 2

Answer:

50m ,53 degree west of south or

50m ,37 degree south of west or

1/tan 3/4 south of west ,50 m

Explanation:

see the picture .