Question

A person holds a bucket of weight 60N. He walks 10m along the horizontal and climb up a vertical distance of 5m. How much work done by the man ?

Answer 1

work done will be 300Joules joules

Answer 2

Where, F =60N, S hori =10m , S ver =5 m

Let W1 and W2 be the work done in two cases.

Then W1=FS cos Θ =60*7*cos 90 =0

[Θ =90,because the force is vertical ]

W2 =60 *5*cos 0 =300 J

Total work done W =W1 +W2 =0+300 =300 J ANS