Physics, asked by nityam138, 1 year ago

a person holds a bucket of weight 60n.He walks 7m along the horizontaland and then climb up a vertically 5m. The work done by man is

Answers

Answered by JazzyAditya
5

When the person walks 7m the work done s F*d

F = 60N

S = 7m

W₁ = 60N * 7m = 420 J


When the person climbs up F = 60N h = 5m

W₂ = 60N * 5m = 300J


Total Work Done = W₁ + W₂ = 420J + 300J = 720J

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