Question

A person in a kayak starts paddling, and it accelerates from 0 to 0.419 m/s in a distance of 0.413 m. If the combined mass of the person and the kayak is 82.2 kg, what is the magnitude of the net force acting on the kayak?

Answer 1

Initial speed, u = 0
final speed, v = 0.419 m/s
distance, s = 0.413 m

we know that

${v}^{2} - {u}^{2} = 2as \\ \\ \Rightarrow {0.419}^{2} - 0 = 2 \times a \times 0.413$

$\Rightarrow a = \frac{ {0.419}^{2} }{2 \times 0.413} \\ \\ \Rightarrow a = 0.213 \: \: \frac{m}{ {s}^{2} }$

Total mass = 82.2 kg

Force = ma = 82.2 × 0.213 = 17.509 N

Net force acting on kayak is 17.509 N

Answer 2

Hi
Nice question

Answer :-

Given :-.

Initial speed, u = 0 m/s
Final speed, v = 0.419 m/s
Distance, s = 0.413 m

Using 3rd equation of motion :-

v² - u² = 2as
( 0.419 )² - (0)² = 2(a)(0.413)
a = (0.419)²/(2)(0.413)
a = 0.213 m/s²

Now,

Combined mass, m = 82.2 kg (given)
Acceleration, a = 0.213 m/s²

Force = ma = 82.2 × 0.213 = 17.509 N

Hope this helps you.