Math, asked by BrainlyHelper, 1 year ago

A person is blindfolded and asked to select a number of out of three ( 2 , -2 , 4 )

Find the probability of getting one of three numbers.

Tejas12311: As he has to select from those three nos. he will always select one among those three only so probability of getting one no out of three is 1

ayushi99: 1/3 possibly

ayushi99: i hope i am right

Perfectionist2212: wrong!!!!

Answers

Answered by HappiestWriter012

There is only chance, so only of three numbers can be selected.

It is confirmed that, one of three numbers will be possible.

Getting one of three events is a certain event.

Hence, Probability = Possible outcomes / Number of out comes = 1/ 1 = 1 .

Perfectionist2212: its a sure event

SiddharthRai007: ek bar me ek hi number choose krega na

Perfectionist2212: its your choice

SiddharthRai007: are ek bar me kitna bhi hoose kre??

Perfectionist2212: see if you can't understand such a simple thing ...no one can help.

SiddharthRai007: are bhai samne to likha hai find the probability of selecting one of the three numbers

SiddharthRai007: samjh gye bhai

kitty289: it is a sure event so yes it will be 1

Palaktiwari: since there are 3 numbers so I think probability will be 1/3.

Palaktiwari: hope it helps.

Answered by 15015

Your question asks to find the probability of getting one number out of three
So, probability is 1/3

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A person is blindfolded and asked to select a number of out of three ( 2 , -2 , 4 ) Find the probability of getting one of three numbers.

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A person is blindfolded and asked to select a number of out of three ( 2 , -2 , 4 )

Find the probability of getting one of three numbers.