Question

A person is carrying a box on his head of weight 60 N and cover a distance of 2m . what will be the value of workdone

120 J

30 J

0 J

1200 J​

Answer 1

Work done= Fd=mgd (gravity = 10m/s²)

60×10×2

=1200 J

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Answer 2

Required Answer:-

The boy is carrying the box on his head. That means, Force is being applied towards up. And he is covering a distance towards left/right.

Work done formula:

$\large{ \therefore{ \underline{ \boxed {\sf{W = Fs \cos( \theta) }}}}}$

Where F is the force applied, s is the distance travelled and cos Θ is the cosine of angle between them.

Now,

• Force is 60 N
• Distance is 2 m

Angle between them will be 90°. That means, cos Θ = cos 90°. And we know that, In trigonometry cos 90° = 0°

Hence,

• Work done = 60 N × 2 m × 0
• Work done = 0 (Option C)

The work done by the boy on carrying the box on his head is 0. Kind of surprising, but that's true in the sense of physics.