Physics, asked by ltzChasmish, 11 months ago

A person is listening to a tone of 500 hertz sitting at a distance of 450 m from the source of the sound what is the time between the successive source?
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Answers

Answered by Anonymous
47

AnsWer:-

The time between the successive source is 2/10³.

Explanation:

Given:-

Frequency of the sound = 500Hz

Distance between the person and the source of sound = 450m

Need to find:-

  • The time between the successive source.

SOLUTION:-

As we know that,

Time period = 1/frequency

Putting values in this formula,

We get;

Time period = 1/frequency

=> 1/500

=> 0.002

=> 0.002/1000

=> 2/10³

Hence,the time between the successive source is 2/10³.

Answered by Aɾꜱɦ
8

\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Solution:-\:\:\:}}}}}} \\

\small\underline\textsf{ Required\: Answer:- }

\:\:\:\:\:\small\underline\textsf{\orange{The} \green{required} \blue{time }\red{period} = \purple{0.002 seconds}} \\\\

\small\underline\textsf{ Given\: Information:- }

\text{ \orange{A person is listening to a tone of 500 hertz sitting}} \\ \text{ \orange{ at a distance of 450 m from the source of the sound.}} \\ \\

\small\underline\textsf{ Need \: to \: find \: out:- }

\:\:\:\:\text{\red{The required time period = ?}}\\\\

\small\underline\textsf{ Formula Used:- }

{\underline{\overline{\mid{\mathsf{\purple{\:\: Time  = \dfrac{1}{Frequency}\:\:} \mid}}}}}\\\\

\small\underline\textsf{ Putting the values:-}

\leadsto\bf Required \: time \: period = \dfrac{1}{500} \\ \\

\leadsto\bf Required \: time \: period = 0.002 \: seconds \\ \\

\small\underline\textsf{ Hence:-}

\underline{\boxed{\textsf{The required time period = {\textbf{0.002 seconds}}}}} \qquad\qquad \bigg\lgroup\bold{Hence \ Solved } \bigg\rgroup

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