a person is moving on a circular path of radius 21m. if he takes 5.5 rounds of the circular track what is the total distance and displacement of the person?
Answers
Answered by
6
Total distance
= 2πr X 5.5
=2 x 22/7 x 21 x 5.5
=726 m
Total displacement
Displacement becomes zero after every one complete round , so after 5 complete round displacement will also be zero.
Displacement
= Displacement of half round
= Diameter of circular path
= 2 x 21
= 42 m
= 2πr X 5.5
=2 x 22/7 x 21 x 5.5
=726 m
Total displacement
Displacement becomes zero after every one complete round , so after 5 complete round displacement will also be zero.
Displacement
= Displacement of half round
= Diameter of circular path
= 2 x 21
= 42 m
Answered by
9
hey friend
total displacements is = 2r = 21×2 = 42m
and
total distance is = 5×(2×pi×r) + 2r
= 5 × (2×22/7×21) + 2×21
= 5×2×66 + 42
= 660 + 42 = 702m
hope it will help you
total displacements is = 2r = 21×2 = 42m
and
total distance is = 5×(2×pi×r) + 2r
= 5 × (2×22/7×21) + 2×21
= 5×2×66 + 42
= 660 + 42 = 702m
hope it will help you
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