Question

A person is moving on a mtorcycle in a ground takes a turn through 60 degrees an his left after every 50 m find displacement after 9th turn

Answer 1

Answer:

don't know a nice question

Answer 2

The magnitude of the displacement suffered by the person moving a motor cycle after 9th turn is 100 m

Explanation:

On taking the turn of 60° every 50 m, the motorcyclist will complete a full hexagon after 6 turns and return to point A as shown in figure

On 7th , 8th and 9th turn he will go from A to G, then from G to H and then from H to I respectively

Initial starting point = A

Final ending point = I

Thus, the displacement = AI = AD

In ΔBCD

DC = BC = 50 m

∴ ∠BCD = 120°

∴ ∠CBD = ∠CDB = 30°

∴ ∠ABD = ∠ABC - ∠CBD = 120° - 30° = 90°

Thus ΔABD is a right angled triangle

In ΔBCD, by sine rule

$\frac{\sin 30^\circ}{CD}=\frac{\sin 120^\circ}{BD}$

$\implies \frac{1/2}{50}=\frac{\sqrt{3}/2}{BD}$

$\implies BD=50\sqrt{3}$

Therefore, in ΔABD

$AD^2=AB^2+BD^2$

$\implies AD^2=50^2+(50\sqrt{3})^2$

$\implies AD^2=50^2(1+3)$

$\implies AD^2=50^2\times 4$

$\implies AD=50\times 2=100$ m

Therefore, the magnitude of displacement is 100 m

Hope this answer is helpful.

Know More:

Q: What is mean by magnitude of displacement ?

Click Here: https://brainly.in/question/9727153

Q: A man walks 4m north then 3m East. the magnitude of displacement of man is?:

Click Here: https://brainly.in/question/11933975