Question

A pipe of diameter 100 mm is to be replaced with 10 pipes of smaller diameter. The approximate value of the smaller diameter aptitude qstn

Answer 1

Answer:

bescann gsggh100 3rd djgzgjb have 10bzh

Answer 2

Answer:

31.6 mm

Step-by-step explanation:

Area of bigger pipe of diameter 100mm = Total area of 10 smaller pipes of diameter x mm

So, Π (100/2)² = 10 x Π (d/2)²

So,  Π (50)² = 10 x Π (d/2)²

So,  2500 = 10 (d/2)²

S0, 250 = (d/2)²

So, d/2 = 15.81

So, d = 31.6 mm -  The approximate value of the smaller diameter