A person is observing the "statue of unity" of sardar vallabhbhai patel of height 182m. From a point on the ground, the angle of elevation of the top of the statue is 60 degree. Find the distance between the base of the statue and the person. Write the answer adjusting to two decimal places.
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shashikalassagar:
182/3 is 60.67
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CONCEPT:
tanA=perpendicular/base
sinA=perpendicular/hypotenuse
cosA=base/hypotenuse
Given:
AB=182m
∠C=60°
Find:
BC=?
Solution:
When base or perpendicular is given, and we need to find eihter of these twO, then we use tan
So, tanC=AB/BC
⇒tan60° =182/BC
⇒√3 =182/BC
⇒BC =182/√3
⇒BC=105.08m
Therefore,the distance between the base of the statue and the person is 105.08 m
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